select *
from a
join b
on a.uid = b.uid
这种情况一般是由于join的key存在严重倾斜导致的,所以需要分别看下在a表和b表里,uid的分布情况:
select uid, count(1) as cnt
from a
group by uid
order by cnt desc
limit 1000
实际情况可能是如下图所示。
如果在sql中通过where filter去掉这些uid,则任务成功。对于这些倾斜的value,可以分开单独处理(通过增加reducer内存等方式)。
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